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144001300564213 is a prime number
BaseRepresentation
bin100000101111011111101010…
…010111100000100011110101
3200212212101112020011202020021
4200233133222113200203311
5122333304130421023323
61230133141220405141
742221515316642461
oct4057375227404365
9625771466152207
10144001300564213
1141979677075a74
12141985002467b1
136247358ab0b51
14277b9b32574a1
15119ac0e74905d
hex82f7ea5e08f5

144001300564213 has 2 divisors, whose sum is σ = 144001300564214. Its totient is φ = 144001300564212.

The previous prime is 144001300564181. The next prime is 144001300564229. The reversal of 144001300564213 is 312465003100441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74748163072804 + 69253137491409 = 8645702^2 + 8321847^2 .

It is a cyclic number.

It is not a de Polignac number, because 144001300564213 - 25 = 144001300564181 is a prime.

It is a super-2 number, since 2×1440013005642132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144001300564243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72000650282106 + 72000650282107.

It is an arithmetic number, because the mean of its divisors is an integer number (72000650282107).

Almost surely, 2144001300564213 is an apocalyptic number.

It is an amenable number.

144001300564213 is a deficient number, since it is larger than the sum of its proper divisors (1).

144001300564213 is an equidigital number, since it uses as much as digits as its factorization.

144001300564213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 144001300564213 its reverse (312465003100441), we get a palindrome (456466303664654).

The spelling of 144001300564213 in words is "one hundred forty-four trillion, one billion, three hundred million, five hundred sixty-four thousand, two hundred thirteen".