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144011978951 is a prime number
BaseRepresentation
bin1000011000011111001…
…0000110100011000111
3111202201102221112020012
42012013302012203013
54324414031311301
6150054100300435
713255515423641
oct2060762064307
9452642845205
10144011978951
115609100a325
1223ab13a171b
1310770b18c39
146d823bd891
153b2d060ebb
hex2187c868c7

144011978951 has 2 divisors, whose sum is σ = 144011978952. Its totient is φ = 144011978950.

The previous prime is 144011978923. The next prime is 144011978953. The reversal of 144011978951 is 159879110441.

It is a strong prime.

It is an emirp because it is prime and its reverse (159879110441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144011978951 - 210 = 144011977927 is a prime.

Together with 144011978953, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 144011978951.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144011978953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72005989475 + 72005989476.

It is an arithmetic number, because the mean of its divisors is an integer number (72005989476).

Almost surely, 2144011978951 is an apocalyptic number.

144011978951 is a deficient number, since it is larger than the sum of its proper divisors (1).

144011978951 is an equidigital number, since it uses as much as digits as its factorization.

144011978951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 50.

The spelling of 144011978951 in words is "one hundred forty-four billion, eleven million, nine hundred seventy-eight thousand, nine hundred fifty-one".