Base | Representation |
---|---|
bin | 101010111010110… |
… | …1110001011010011 |
3 | 10201100220000002121 |
4 | 1111311232023103 |
5 | 10422134134011 |
6 | 354523155111 |
7 | 50455016524 |
oct | 12565561323 |
9 | 3640800077 |
10 | 1440146131 |
11 | 679a1a116 |
12 | 342375a97 |
13 | 19c496998 |
14 | d93a284b |
15 | 86674e71 |
hex | 55d6e2d3 |
1440146131 has 2 divisors, whose sum is σ = 1440146132. Its totient is φ = 1440146130.
The previous prime is 1440146101. The next prime is 1440146159. The reversal of 1440146131 is 1316410441.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1440146131 is a prime.
It is a super-2 number, since 2×14401461312 = 4148041757268538322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1440146096 and 1440146105.
It is not a weakly prime, because it can be changed into another prime (1440146101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720073065 + 720073066.
It is an arithmetic number, because the mean of its divisors is an integer number (720073066).
Almost surely, 21440146131 is an apocalyptic number.
1440146131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440146131 is an equidigital number, since it uses as much as digits as its factorization.
1440146131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
The square root of 1440146131 is about 37949.2573181610. The cubic root of 1440146131 is about 1129.2814318474.
Adding to 1440146131 its reverse (1316410441), we get a palindrome (2756556572).
The spelling of 1440146131 in words is "one billion, four hundred forty million, one hundred forty-six thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •