Search a number
-
+
14402331211232 = 25450072850351
BaseRepresentation
bin1101000110010100110111…
…0101011111010111100000
31212222211221020002010101002
43101211031311133113200
53341431433242224412
650344201205131132
73014351123254556
oct321451565372740
955884836063332
1014402331211232
114652aa3556538
1217473276b9aa8
13806198544803
1437b1100a5bd6
1519e9872d0dc2
hexd194dd5f5e0

14402331211232 has 12 divisors (see below), whose sum is σ = 28354589572176. Its totient is φ = 7201165605600.

The previous prime is 14402331211223. The next prime is 14402331211277. The reversal of 14402331211232 is 23211213320441.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 14402331211195 and 14402331211204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225036425144 + ... + 225036425207.

It is an arithmetic number, because the mean of its divisors is an integer number (2362882464348).

Almost surely, 214402331211232 is an apocalyptic number.

It is an amenable number.

14402331211232 is a deficient number, since it is larger than the sum of its proper divisors (13952258360944).

14402331211232 is an equidigital number, since it uses as much as digits as its factorization.

14402331211232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450072850361 (or 450072850353 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14402331211232 its reverse (23211213320441), we get a palindrome (37613544531673).

The spelling of 14402331211232 in words is "fourteen trillion, four hundred two billion, three hundred thirty-one million, two hundred eleven thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 32 450072850351 900145700702 1800291401404 3600582802808 7201165605616 14402331211232