Base | Representation |
---|---|
bin | 1101000110011000110110… |
… | …1010010001010110000101 |
3 | 1212222221200211222102221011 |
4 | 3101212031222101112011 |
5 | 3341441131403341122 |
6 | 50344455340122221 |
7 | 3014416505026033 |
oct | 321461552212605 |
9 | 55887624872834 |
10 | 14403402012037 |
11 | 46534a2a37a85 |
12 | 1747586236371 |
13 | 806309340b5c |
14 | 37b1b23a3553 |
15 | 19e9eb2ea377 |
hex | d198da91585 |
14403402012037 has 2 divisors, whose sum is σ = 14403402012038. Its totient is φ = 14403402012036.
The previous prime is 14403402012031. The next prime is 14403402012049. The reversal of 14403402012037 is 73021020430441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13952421266436 + 450980745601 = 3735294^2 + 671551^2 .
It is a cyclic number.
It is not a de Polignac number, because 14403402012037 - 211 = 14403402009989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14403402012031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201701006018 + 7201701006019.
It is an arithmetic number, because the mean of its divisors is an integer number (7201701006019).
Almost surely, 214403402012037 is an apocalyptic number.
It is an amenable number.
14403402012037 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403402012037 is an equidigital number, since it uses as much as digits as its factorization.
14403402012037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 14403402012037 its reverse (73021020430441), we get a palindrome (87424422442478).
The spelling of 14403402012037 in words is "fourteen trillion, four hundred three billion, four hundred two million, twelve thousand, thirty-seven".
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