14403402012031 has 2 divisors, whose sum is σ = 14403402012032. Its totient is φ = 14403402012030.

The previous prime is 14403402011951. The next prime is 14403402012037. The reversal of 14403402012031 is 13021020430441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14403402012031 - 2⁷ = 14403402011903 is a prime.

It is a super-2 number, since 2×14403402012031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14403402011987 and 14403402012005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14403402012037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201701006015 + 7201701006016.

It is an arithmetic number, because the mean of its divisors is an integer number (7201701006016).

Almost surely, 2^{14403402012031} is an apocalyptic number.

14403402012031 is a deficient number, since it is larger than the sum of its proper divisors (1).

14403402012031 is an equidigital number, since it uses as much as digits as its factorization.

14403402012031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14403402012031 its reverse (13021020430441), we get a palindrome (27424422442472).

The spelling of 14403402012031 in words is "fourteen trillion, four hundred three billion, four hundred two million, twelve thousand, thirty-one".