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144034331297407 is a prime number
BaseRepresentation
bin100000101111111110011011…
…001001110000011001111111
3200212222112210012022211221221
4200233332123021300121333
5122334324302303004112
61230200242555534211
742224065000355245
oct4057763311603177
9625875705284857
10144034331297407
1141991687060781
12141a299a15a367
13624a4c102b0a5
14277d427dc8795
15119b9e4487e07
hex82ff9b27067f

144034331297407 has 2 divisors, whose sum is σ = 144034331297408. Its totient is φ = 144034331297406.

The previous prime is 144034331297317. The next prime is 144034331297459. The reversal of 144034331297407 is 704792133430441.

It is an a-pointer prime, because the next prime (144034331297459) can be obtained adding 144034331297407 to its sum of digits (52).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144034331297407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144034331292407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017165648703 + 72017165648704.

It is an arithmetic number, because the mean of its divisors is an integer number (72017165648704).

Almost surely, 2144034331297407 is an apocalyptic number.

144034331297407 is a deficient number, since it is larger than the sum of its proper divisors (1).

144034331297407 is an equidigital number, since it uses as much as digits as its factorization.

144034331297407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 52.

The spelling of 144034331297407 in words is "one hundred forty-four trillion, thirty-four billion, three hundred thirty-one million, two hundred ninety-seven thousand, four hundred seven".