Base | Representation |
---|---|
bin | 100000101111111110011011… |
… | …001001110000011001111111 |
3 | 200212222112210012022211221221 |
4 | 200233332123021300121333 |
5 | 122334324302303004112 |
6 | 1230200242555534211 |
7 | 42224065000355245 |
oct | 4057763311603177 |
9 | 625875705284857 |
10 | 144034331297407 |
11 | 41991687060781 |
12 | 141a299a15a367 |
13 | 624a4c102b0a5 |
14 | 277d427dc8795 |
15 | 119b9e4487e07 |
hex | 82ff9b27067f |
144034331297407 has 2 divisors, whose sum is σ = 144034331297408. Its totient is φ = 144034331297406.
The previous prime is 144034331297317. The next prime is 144034331297459. The reversal of 144034331297407 is 704792133430441.
It is an a-pointer prime, because the next prime (144034331297459) can be obtained adding 144034331297407 to its sum of digits (52).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144034331297407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144034331292407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017165648703 + 72017165648704.
It is an arithmetic number, because the mean of its divisors is an integer number (72017165648704).
Almost surely, 2144034331297407 is an apocalyptic number.
144034331297407 is a deficient number, since it is larger than the sum of its proper divisors (1).
144034331297407 is an equidigital number, since it uses as much as digits as its factorization.
144034331297407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6096384, while the sum is 52.
The spelling of 144034331297407 in words is "one hundred forty-four trillion, thirty-four billion, three hundred thirty-one million, two hundred ninety-seven thousand, four hundred seven".
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