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144034331297663 is a prime number
BaseRepresentation
bin100000101111111110011011…
…001001110000011101111111
3200212222112210012022212022102
4200233332123021300131333
5122334324302303011123
61230200242555535315
742224065000356062
oct4057763311603577
9625875705285272
10144034331297663
1141991687060994
12141a299a15a53b
13624a4c102b241
14277d427dc88d9
15119b9e4488028
hex82ff9b27077f

144034331297663 has 2 divisors, whose sum is σ = 144034331297664. Its totient is φ = 144034331297662.

The previous prime is 144034331297653. The next prime is 144034331297669. The reversal of 144034331297663 is 366792133430441.

It is a strong prime.

It is an emirp because it is prime and its reverse (366792133430441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144034331297663 - 28 = 144034331297407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144034331297599 and 144034331297608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144034331297669) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017165648831 + 72017165648832.

It is an arithmetic number, because the mean of its divisors is an integer number (72017165648832).

Almost surely, 2144034331297663 is an apocalyptic number.

144034331297663 is a deficient number, since it is larger than the sum of its proper divisors (1).

144034331297663 is an equidigital number, since it uses as much as digits as its factorization.

144034331297663 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23514624, while the sum is 56.

The spelling of 144034331297663 in words is "one hundred forty-four trillion, thirty-four billion, three hundred thirty-one million, two hundred ninety-seven thousand, six hundred sixty-three".