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144035454625133 is a prime number
BaseRepresentation
bin100000101111111111011110…
…000110111010010101101101
3200212222122200111001210220112
4200233333132012322111231
5122334334102341001013
61230200550244425405
742224134560450221
oct4057773606722555
9625878614053815
10144035454625133
11419921031594a5
12141a30523a8265
13624a63c988a56
14277d4d327a781
15119ba5cdcaba8
hex82ffde1ba56d

144035454625133 has 2 divisors, whose sum is σ = 144035454625134. Its totient is φ = 144035454625132.

The previous prime is 144035454625123. The next prime is 144035454625141. The reversal of 144035454625133 is 331526454530441.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95838578519524 + 48196876105609 = 9789718^2 + 6942397^2 .

It is a cyclic number.

It is not a de Polignac number, because 144035454625133 - 28 = 144035454624877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144035454625123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017727312566 + 72017727312567.

It is an arithmetic number, because the mean of its divisors is an integer number (72017727312567).

Almost surely, 2144035454625133 is an apocalyptic number.

It is an amenable number.

144035454625133 is a deficient number, since it is larger than the sum of its proper divisors (1).

144035454625133 is an equidigital number, since it uses as much as digits as its factorization.

144035454625133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368000, while the sum is 50.

The spelling of 144035454625133 in words is "one hundred forty-four trillion, thirty-five billion, four hundred fifty-four million, six hundred twenty-five thousand, one hundred thirty-three".