144044331400421 has 2 divisors, whose sum is σ = 144044331400422. Its totient is φ = 144044331400420.

The previous prime is 144044331400373. The next prime is 144044331400423. The reversal of 144044331400421 is 124004133440441.

144044331400421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87385365744196 + 56658965656225 = 9348014^2 + 7527215^2 .

It is an emirp because it is prime and its reverse (124004133440441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144044331400421 is a prime.

It is a super-2 number, since 2×144044331400421² (a number of 29 digits) contains 22 as substring.

Together with 144044331400423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144044331400423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72022165700210 + 72022165700211.

It is an arithmetic number, because the mean of its divisors is an integer number (72022165700211).

Almost surely, 2^{144044331400421} is an apocalyptic number.

It is an amenable number.

144044331400421 is a deficient number, since it is larger than the sum of its proper divisors (1).

144044331400421 is an equidigital number, since it uses as much as digits as its factorization.

144044331400421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 144044331400421 its reverse (124004133440441), we get a palindrome (268048464840862).

The spelling of 144044331400421 in words is "one hundred forty-four trillion, forty-four billion, three hundred thirty-one million, four hundred thousand, four hundred twenty-one".