Base | Representation |
---|---|
bin | 10100111110000100001… |
… | …100110111111010010101 |
3 | 12002202112222221221111021 |
4 | 110332010030313322111 |
5 | 142102213143331123 |
6 | 3022000113041141 |
7 | 206053054665331 |
oct | 24760414677225 |
9 | 5082488857437 |
10 | 1441032011413 |
11 | 506158003825 |
12 | 1b33468561b1 |
13 | a5b72723c77 |
14 | 4da63c987c1 |
15 | 2774054cc5d |
hex | 14f84337e95 |
1441032011413 has 2 divisors, whose sum is σ = 1441032011414. Its totient is φ = 1441032011412.
The previous prime is 1441032011407. The next prime is 1441032011473. The reversal of 1441032011413 is 3141102301441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1404374313969 + 36657697444 = 1185063^2 + 191462^2 .
It is a cyclic number.
It is not a de Polignac number, because 1441032011413 - 217 = 1441031880341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1441032011473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720516005706 + 720516005707.
It is an arithmetic number, because the mean of its divisors is an integer number (720516005707).
Almost surely, 21441032011413 is an apocalyptic number.
It is an amenable number.
1441032011413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441032011413 is an equidigital number, since it uses as much as digits as its factorization.
1441032011413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1441032011413 its reverse (3141102301441), we get a palindrome (4582134312854).
The spelling of 1441032011413 in words is "one trillion, four hundred forty-one billion, thirty-two million, eleven thousand, four hundred thirteen".
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