Base | Representation |
---|---|
bin | 10100111110001001000… |
… | …101101001011111010011 |
3 | 12002202202201020120100221 |
4 | 110332021011221133103 |
5 | 142102400141102121 |
6 | 3022012202253511 |
7 | 206055101626135 |
oct | 24761105513723 |
9 | 5082681216327 |
10 | 1441114003411 |
11 | 50619a315605 |
12 | 1b336a1b7297 |
13 | a5b86700c44 |
14 | 4da70b1d055 |
15 | 27747846b41 |
hex | 14f891697d3 |
1441114003411 has 2 divisors, whose sum is σ = 1441114003412. Its totient is φ = 1441114003410.
The previous prime is 1441114003319. The next prime is 1441114003421. The reversal of 1441114003411 is 1143004111441.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1143004111441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1441114003411 - 215 = 1441113970643 is a prime.
It is not a weakly prime, because it can be changed into another prime (1441114003421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720557001705 + 720557001706.
It is an arithmetic number, because the mean of its divisors is an integer number (720557001706).
Almost surely, 21441114003411 is an apocalyptic number.
1441114003411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441114003411 is an equidigital number, since it uses as much as digits as its factorization.
1441114003411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1441114003411 its reverse (1143004111441), we get a palindrome (2584118114852).
The spelling of 1441114003411 in words is "one trillion, four hundred forty-one billion, one hundred fourteen million, three thousand, four hundred eleven".
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