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1441131253 is a prime number
BaseRepresentation
bin101010111100101…
…1110101011110101
310201102202001102121
41111321132223311
510422412200003
6355000235541
750466261562
oct12571365365
93642661377
101441131253
1167a532271
1234276bbb1
1319c7501b3
14d957b869
15867bbcbd
hex55e5eaf5

1441131253 has 2 divisors, whose sum is σ = 1441131254. Its totient is φ = 1441131252.

The previous prime is 1441131229. The next prime is 1441131269. The reversal of 1441131253 is 3521311441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1440809764 + 321489 = 37958^2 + 567^2 .

It is a cyclic number.

It is not a de Polignac number, because 1441131253 - 25 = 1441131221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1441131353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720565626 + 720565627.

It is an arithmetic number, because the mean of its divisors is an integer number (720565627).

Almost surely, 21441131253 is an apocalyptic number.

It is an amenable number.

1441131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441131253 is an equidigital number, since it uses as much as digits as its factorization.

1441131253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 25.

The square root of 1441131253 is about 37962.2345627862. The cubic root of 1441131253 is about 1129.5388655419.

Adding to 1441131253 its reverse (3521311441), we get a palindrome (4962442694).

The spelling of 1441131253 in words is "one billion, four hundred forty-one million, one hundred thirty-one thousand, two hundred fifty-three".