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1441200031319 is a prime number
BaseRepresentation
bin10100111110001110001…
…101110100011001010111
312002202222201010020110202
4110332032031310121113
5142103034202000234
63022024514211115
7206060165066306
oct24761615643127
95082881106422
101441200031319
11506233933654
121b3392b83a9b
13a5b9b491c29
144da7c31443d
152775018b77e
hex14f8e374657

1441200031319 has 2 divisors, whose sum is σ = 1441200031320. Its totient is φ = 1441200031318.

The previous prime is 1441200031307. The next prime is 1441200031333. The reversal of 1441200031319 is 9131300021441.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1441200031319 - 240 = 341688403543 is a prime.

It is a super-2 number, since 2×14412000313192 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1441200031291 and 1441200031300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1441200031819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720600015659 + 720600015660.

It is an arithmetic number, because the mean of its divisors is an integer number (720600015660).

Almost surely, 21441200031319 is an apocalyptic number.

1441200031319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441200031319 is an equidigital number, since it uses as much as digits as its factorization.

1441200031319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 1441200031319 in words is "one trillion, four hundred forty-one billion, two hundred million, thirty-one thousand, three hundred nineteen".