Base | Representation |
---|---|
bin | 100000110001001110001101… |
… | …101010010100111010100011 |
3 | 200220021201220220012100010202 |
4 | 200301032031222110322203 |
5 | 122342230232100103301 |
6 | 1230303452125415415 |
7 | 42233220026025314 |
oct | 4061161552247243 |
9 | 626251826170122 |
10 | 144120004300451 |
11 | 41a14a50254a23 |
12 | 141b7509a0a56b |
13 | 62555c556aa2a |
14 | 278363437260b |
15 | 119dd5a9eb66b |
hex | 83138da94ea3 |
144120004300451 has 2 divisors, whose sum is σ = 144120004300452. Its totient is φ = 144120004300450.
The previous prime is 144120004300411. The next prime is 144120004300453. The reversal of 144120004300451 is 154003400021441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144120004300451 is a prime.
Together with 144120004300453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (144120004300453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72060002150225 + 72060002150226.
It is an arithmetic number, because the mean of its divisors is an integer number (72060002150226).
Almost surely, 2144120004300451 is an apocalyptic number.
144120004300451 is a deficient number, since it is larger than the sum of its proper divisors (1).
144120004300451 is an equidigital number, since it uses as much as digits as its factorization.
144120004300451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 144120004300451 its reverse (154003400021441), we get a palindrome (298123404321892).
The spelling of 144120004300451 in words is "one hundred forty-four trillion, one hundred twenty billion, four million, three hundred thousand, four hundred fifty-one".
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