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14413131414103 is a prime number
BaseRepresentation
bin1101000110111101000110…
…0100111111101001010111
31220000212210220120021110211
43101233101210333221113
53342121043120222403
650353145015030251
73015212555416522
oct321572144775127
956025726507424
1014413131414103
114657635a2a834
12174944066b387
138071c9c562b6
1437b856607bb9
1519edba55606d
hexd1bd193fa57

14413131414103 has 2 divisors, whose sum is σ = 14413131414104. Its totient is φ = 14413131414102.

The previous prime is 14413131414053. The next prime is 14413131414107. The reversal of 14413131414103 is 30141413131441.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (30141413131441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14413131414103 - 221 = 14413129316951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14413131414107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206565707051 + 7206565707052.

It is an arithmetic number, because the mean of its divisors is an integer number (7206565707052).

Almost surely, 214413131414103 is an apocalyptic number.

14413131414103 is a deficient number, since it is larger than the sum of its proper divisors (1).

14413131414103 is an equidigital number, since it uses as much as digits as its factorization.

14413131414103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 14413131414103 its reverse (30141413131441), we get a palindrome (44554544545544).

The spelling of 14413131414103 in words is "fourteen trillion, four hundred thirteen billion, one hundred thirty-one million, four hundred fourteen thousand, one hundred three".