Base | Representation |
---|---|
bin | 1101000110111101011001… |
… | …0010010110010101110111 |
3 | 1220000220000102012210202221 |
4 | 3101233112102112111313 |
5 | 3342121223331144112 |
6 | 50353200520143211 |
7 | 3015214535041342 |
oct | 321572622262567 |
9 | 56026012183687 |
10 | 14413210412407 |
11 | 4657676587394 |
12 | 1749463007b07 |
13 | 807210425761 |
14 | 37b862ccd459 |
15 | 19edc245ce07 |
hex | d1bd6496577 |
14413210412407 has 2 divisors, whose sum is σ = 14413210412408. Its totient is φ = 14413210412406.
The previous prime is 14413210412339. The next prime is 14413210412411. The reversal of 14413210412407 is 70421401231441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14413210412407 - 223 = 14413202023799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14413210412437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206605206203 + 7206605206204.
It is an arithmetic number, because the mean of its divisors is an integer number (7206605206204).
Almost surely, 214413210412407 is an apocalyptic number.
14413210412407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14413210412407 is an equidigital number, since it uses as much as digits as its factorization.
14413210412407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 14413210412407 its reverse (70421401231441), we get a palindrome (84834611643848).
The spelling of 14413210412407 in words is "fourteen trillion, four hundred thirteen billion, two hundred ten million, four hundred twelve thousand, four hundred seven".
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