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14413240150117 is a prime number
BaseRepresentation
bin1101000110111101100000…
…0011110010100001100101
31220000220002111011122020121
43101233120003302201211
53342121303434300432
650353203501401541
73015215345565244
oct321573003624145
956026074148217
1014413240150117
114657691348806
121749470b692b1
13807216638233
1437b866c3095b
1519edc4d84197
hexd1bd80f2865

14413240150117 has 2 divisors, whose sum is σ = 14413240150118. Its totient is φ = 14413240150116.

The previous prime is 14413240150103. The next prime is 14413240150163. The reversal of 14413240150117 is 71105104231441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14395604575716 + 17635574401 = 3794154^2 + 132799^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14413240150117 is a prime.

It is a super-2 number, since 2×144132401501172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14413240150217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206620075058 + 7206620075059.

It is an arithmetic number, because the mean of its divisors is an integer number (7206620075059).

Almost surely, 214413240150117 is an apocalyptic number.

It is an amenable number.

14413240150117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14413240150117 is an equidigital number, since it uses as much as digits as its factorization.

14413240150117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 34.

Adding to 14413240150117 its reverse (71105104231441), we get a palindrome (85518344381558).

The spelling of 14413240150117 in words is "fourteen trillion, four hundred thirteen billion, two hundred forty million, one hundred fifty thousand, one hundred seventeen".