Base | Representation |
---|---|
bin | 100000110001101101000100… |
… | …010010010111001111110111 |
3 | 200220101220102200201200002021 |
4 | 200301231010102113033313 |
5 | 122343301104023121101 |
6 | 1230331011325054011 |
7 | 42235502006346043 |
oct | 4061550422271767 |
9 | 626356380650067 |
10 | 144153133020151 |
11 | 41a28000586412 |
12 | 14201a146b7307 |
13 | 6258774ba5158 |
14 | 278509812d023 |
15 | 119eb491435a1 |
hex | 831b444973f7 |
144153133020151 has 2 divisors, whose sum is σ = 144153133020152. Its totient is φ = 144153133020150.
The previous prime is 144153133020137. The next prime is 144153133020167. The reversal of 144153133020151 is 151020331351441.
144153133020151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144153133020151 - 219 = 144153132495863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144153133021151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72076566510075 + 72076566510076.
It is an arithmetic number, because the mean of its divisors is an integer number (72076566510076).
Almost surely, 2144153133020151 is an apocalyptic number.
144153133020151 is a deficient number, since it is larger than the sum of its proper divisors (1).
144153133020151 is an equidigital number, since it uses as much as digits as its factorization.
144153133020151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 144153133020151 its reverse (151020331351441), we get a palindrome (295173464371592).
The spelling of 144153133020151 in words is "one hundred forty-four trillion, one hundred fifty-three billion, one hundred thirty-three million, twenty thousand, one hundred fifty-one".
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