Base | Representation |
---|---|
bin | 11010110110100001… |
… | …01011010001110101 |
3 | 1101012200020200110021 |
4 | 31123100223101311 |
5 | 214010444000432 |
6 | 10342252525141 |
7 | 1020145656601 |
oct | 153320532165 |
9 | 41180220407 |
10 | 14416000117 |
11 | 6128502292 |
12 | 2963a807b1 |
13 | 14898630ac |
14 | 9aa844501 |
15 | 595907697 |
hex | 35b42b475 |
14416000117 has 2 divisors, whose sum is σ = 14416000118. Its totient is φ = 14416000116.
The previous prime is 14416000043. The next prime is 14416000133. The reversal of 14416000117 is 71100061441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10941369201 + 3474630916 = 104601^2 + 58946^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14416000117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14416000091 and 14416000100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14416000517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7208000058 + 7208000059.
It is an arithmetic number, because the mean of its divisors is an integer number (7208000059).
Almost surely, 214416000117 is an apocalyptic number.
It is an amenable number.
14416000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14416000117 is an equidigital number, since it uses as much as digits as its factorization.
14416000117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 14416000117 its reverse (71100061441), we get a palindrome (85516061558).
The spelling of 14416000117 in words is "fourteen billion, four hundred sixteen million, one hundred seventeen", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •