14420124133 has 2 divisors, whose sum is σ = 14420124134. Its totient is φ = 14420124132.

The previous prime is 14420124109. The next prime is 14420124139. The reversal of 14420124133 is 33142102441.

14420124133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8200751364 + 6219372769 = 90558^2 + 78863^2 .

It is a cyclic number.

It is not a de Polignac number, because 14420124133 - 2⁵ = 14420124101 is a prime.

It is a super-2 number, since 2×14420124133² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14420124098 and 14420124107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14420124139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210062066 + 7210062067.

It is an arithmetic number, because the mean of its divisors is an integer number (7210062067).

Almost surely, 2^14420124133 is an apocalyptic number.

It is an amenable number.

14420124133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14420124133 is an equidigital number, since it uses as much as digits as its factorization.

14420124133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14420124133 its reverse (33142102441), we get a palindrome (47562226574).

The spelling of 14420124133 in words is "fourteen billion, four hundred twenty million, one hundred twenty-four thousand, one hundred thirty-three".