1442013312013 has 2 divisors, whose sum is σ = 1442013312014. Its totient is φ = 1442013312012.

The previous prime is 1442013312001. The next prime is 1442013312017. The reversal of 1442013312013 is 3102133102441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1013169072969 + 428844239044 = 1006563^2 + 654862^2 .

It is an emirp because it is prime and its reverse (3102133102441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1442013312013 - 2¹³ = 1442013303821 is a prime.

It is a super-2 number, since 2×1442013312013² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1442013312017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721006656006 + 721006656007.

It is an arithmetic number, because the mean of its divisors is an integer number (721006656007).

Almost surely, 2^{1442013312013} is an apocalyptic number.

It is an amenable number.

1442013312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1442013312013 is an equidigital number, since it uses as much as digits as its factorization.

1442013312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1442013312013 its reverse (3102133102441), we get a palindrome (4544146414454).

The spelling of 1442013312013 in words is "one trillion, four hundred forty-two billion, thirteen million, three hundred twelve thousand, thirteen".