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1442122443407 is a prime number
BaseRepresentation
bin10100111111000101001…
…100100010101010001111
312002212100222210121222102
4110333011030202222033
5142111431321142112
63022300224505315
7206122065341342
oct24770514425217
95085328717872
101442122443407
11506667583498
121b35aba7b23b
13a5cb76048b9
144db28a26459
15277a6143bc2
hex14fc5322a8f

1442122443407 has 2 divisors, whose sum is σ = 1442122443408. Its totient is φ = 1442122443406.

The previous prime is 1442122443397. The next prime is 1442122443457. The reversal of 1442122443407 is 7043442212441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1442122443407 - 212 = 1442122439311 is a prime.

It is a super-3 number, since 3×14421224434073 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1442122443457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721061221703 + 721061221704.

It is an arithmetic number, because the mean of its divisors is an integer number (721061221704).

Almost surely, 21442122443407 is an apocalyptic number.

1442122443407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1442122443407 is an equidigital number, since it uses as much as digits as its factorization.

1442122443407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172032, while the sum is 38.

Adding to 1442122443407 its reverse (7043442212441), we get a palindrome (8485564655848).

The spelling of 1442122443407 in words is "one trillion, four hundred forty-two billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred seven".