Base | Representation |
---|---|
bin | 10100111111000101001… |
… | …100100010101010001111 |
3 | 12002212100222210121222102 |
4 | 110333011030202222033 |
5 | 142111431321142112 |
6 | 3022300224505315 |
7 | 206122065341342 |
oct | 24770514425217 |
9 | 5085328717872 |
10 | 1442122443407 |
11 | 506667583498 |
12 | 1b35aba7b23b |
13 | a5cb76048b9 |
14 | 4db28a26459 |
15 | 277a6143bc2 |
hex | 14fc5322a8f |
1442122443407 has 2 divisors, whose sum is σ = 1442122443408. Its totient is φ = 1442122443406.
The previous prime is 1442122443397. The next prime is 1442122443457. The reversal of 1442122443407 is 7043442212441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1442122443407 - 212 = 1442122439311 is a prime.
It is a super-3 number, since 3×14421224434073 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1442122443457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721061221703 + 721061221704.
It is an arithmetic number, because the mean of its divisors is an integer number (721061221704).
Almost surely, 21442122443407 is an apocalyptic number.
1442122443407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1442122443407 is an equidigital number, since it uses as much as digits as its factorization.
1442122443407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172032, while the sum is 38.
Adding to 1442122443407 its reverse (7043442212441), we get a palindrome (8485564655848).
The spelling of 1442122443407 in words is "one trillion, four hundred forty-two billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred seven".
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