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14421301457 is a prime number
BaseRepresentation
bin11010110111001001…
…11001100011010001
31101020001020000112012
431123210321203101
5214013323121312
610343002312305
71020242016443
oct153344714321
941201200465
1014421301457
1161304a3262
1229657b8695
13148a99b094
149ab424493
15596103322
hex35b9398d1

14421301457 has 2 divisors, whose sum is σ = 14421301458. Its totient is φ = 14421301456.

The previous prime is 14421301441. The next prime is 14421301459. The reversal of 14421301457 is 75410312441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9872608321 + 4548693136 = 99361^2 + 67444^2 .

It is an emirp because it is prime and its reverse (75410312441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14421301457 - 24 = 14421301441 is a prime.

Together with 14421301459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14421301459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210650728 + 7210650729.

It is an arithmetic number, because the mean of its divisors is an integer number (7210650729).

Almost surely, 214421301457 is an apocalyptic number.

It is an amenable number.

14421301457 is a deficient number, since it is larger than the sum of its proper divisors (1).

14421301457 is an equidigital number, since it uses as much as digits as its factorization.

14421301457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 32.

Adding to 14421301457 its reverse (75410312441), we get a palindrome (89831613898).

The spelling of 14421301457 in words is "fourteen billion, four hundred twenty-one million, three hundred one thousand, four hundred fifty-seven".