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1442323332013 is a prime number
BaseRepresentation
bin10100111111010001001…
…010110111101110101101
312002212212222210211100011
4110333101022313232231
5142112334233111023
63022332202333221
7206130055016404
oct24772112675655
95085788724304
101442323332013
1150675aa13033
121b36471ba211
13a601a1104b5
144db4759a63b
15277b8ac650d
hex14fd12b7bad

1442323332013 has 2 divisors, whose sum is σ = 1442323332014. Its totient is φ = 1442323332012.

The previous prime is 1442323331987. The next prime is 1442323332029. The reversal of 1442323332013 is 3102333232441.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1170025132329 + 272298199684 = 1081677^2 + 521822^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1442323332013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1442323332413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 721161666006 + 721161666007.

It is an arithmetic number, because the mean of its divisors is an integer number (721161666007).

Almost surely, 21442323332013 is an apocalyptic number.

It is an amenable number.

1442323332013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1442323332013 is an equidigital number, since it uses as much as digits as its factorization.

1442323332013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1442323332013 its reverse (3102333232441), we get a palindrome (4544656564454).

The spelling of 1442323332013 in words is "one trillion, four hundred forty-two billion, three hundred twenty-three million, three hundred thirty-two thousand, thirteen".