14426231 has 2 divisors, whose sum is σ = 14426232. Its totient is φ = 14426230.

The previous prime is 14426213. The next prime is 14426233. The reversal of 14426231 is 13262441.

14426231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (14426213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14426231 - 2¹⁰ = 14425207 is a prime.

It is a super-2 number, since 2×14426231² = 416232281730722, which contains 22 as substring.

Together with 14426233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14426197 and 14426206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14426233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7213115 + 7213116.

It is an arithmetic number, because the mean of its divisors is an integer number (7213116).

Almost surely, 2^14426231 is an apocalyptic number.

14426231 is a deficient number, since it is larger than the sum of its proper divisors (1).

14426231 is an equidigital number, since it uses as much as digits as its factorization.

14426231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 23.

The square root of 14426231 is about 3798.1878573867. The cubic root of 14426231 is about 243.4357145123.

Adding to 14426231 its reverse (13262441), we get a palindrome (27688672).

The spelling of 14426231 in words is "fourteen million, four hundred twenty-six thousand, two hundred thirty-one".