144312153521 has 2 divisors, whose sum is σ = 144312153522. Its totient is φ = 144312153520.

The previous prime is 144312153431. The next prime is 144312153523. The reversal of 144312153521 is 125351213441.

144312153521 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72975619600 + 71336533921 = 270140^2 + 267089^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-144312153521 is a prime.

It is a super-3 number, since 3×144312153521³ (a number of 34 digits) contains 333 as substring.

Together with 144312153523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (144312153523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72156076760 + 72156076761.

It is an arithmetic number, because the mean of its divisors is an integer number (72156076761).

Almost surely, 2^144312153521 is an apocalyptic number.

It is an amenable number.

144312153521 is a deficient number, since it is larger than the sum of its proper divisors (1).

144312153521 is an equidigital number, since it uses as much as digits as its factorization.

144312153521 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 32.

Adding to 144312153521 its reverse (125351213441), we get a palindrome (269663366962).

The spelling of 144312153521 in words is "one hundred forty-four billion, three hundred twelve million, one hundred fifty-three thousand, five hundred twenty-one".