Base | Representation |
---|---|
bin | 100000110100001011101001… |
… | …101110110001100001101000 |
3 | 200221000011221202111002120121 |
4 | 200310023221232301201220 |
5 | 122404043322040324000 |
6 | 1230541132123533024 |
7 | 42254010462440653 |
oct | 4064135156614150 |
9 | 627004852432517 |
10 | 144323412433000 |
11 | 41a932408a6599 |
12 | 1422aa1698a174 |
13 | 626b84099c588 |
14 | 278d40cd3a89a |
15 | 11a42b3282b1a |
hex | 8342e9bb1868 |
144323412433000 has 128 divisors (see below), whose sum is σ = 338015170864800. Its totient is φ = 57678382080000.
The previous prime is 144323412432977. The next prime is 144323412433019. The reversal of 144323412433000 is 334214323441.
144323412433000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 16 ways, for example, as 1737698695524 + 142585713737476 = 1318218^2 + 11940926^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6024257022 + ... + 6024280978.
Almost surely, 2144323412433000 is an apocalyptic number.
144323412433000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 144323412433000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169007585432400).
144323412433000 is an abundant number, since it is smaller than the sum of its proper divisors (193691758431800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
144323412433000 is a wasteful number, since it uses less digits than its factorization.
144323412433000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29048 (or 29034 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 144323412433000 its reverse (334214323441), we get a palindrome (144657626756441).
The spelling of 144323412433000 in words is "one hundred forty-four trillion, three hundred twenty-three billion, four hundred twelve million, four hundred thirty-three thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •