Search a number
-
+
14433121231 is a prime number
BaseRepresentation
bin11010111000100011…
…11111001111001111
31101020212110112012121
431130101333033033
5214024334334411
610344103513411
71020444335434
oct153421771717
941225415177
1014433121231
116137136671
122969758867
131490279029
149acc1db8b
1559718a571
hex35c47f3cf

14433121231 has 2 divisors, whose sum is σ = 14433121232. Its totient is φ = 14433121230.

The previous prime is 14433121177. The next prime is 14433121303. The reversal of 14433121231 is 13212133441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14433121231 - 213 = 14433113039 is a prime.

It is a super-2 number, since 2×144331212312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14433121196 and 14433121205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14433121931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7216560615 + 7216560616.

It is an arithmetic number, because the mean of its divisors is an integer number (7216560616).

Almost surely, 214433121231 is an apocalyptic number.

14433121231 is a deficient number, since it is larger than the sum of its proper divisors (1).

14433121231 is an equidigital number, since it uses as much as digits as its factorization.

14433121231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 25.

Adding to 14433121231 its reverse (13212133441), we get a palindrome (27645254672).

The spelling of 14433121231 in words is "fourteen billion, four hundred thirty-three million, one hundred twenty-one thousand, two hundred thirty-one".