14434321011041 has 2 divisors, whose sum is σ = 14434321011042. Its totient is φ = 14434321011040.

The previous prime is 14434321011037. The next prime is 14434321011043. The reversal of 14434321011041 is 14011012343441.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13802302371025 + 632018640016 = 3715145^2 + 794996^2 .

It is a cyclic number.

It is not a de Polignac number, because 14434321011041 - 2² = 14434321011037 is a prime.

Together with 14434321011043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14434321010995 and 14434321011013.

It is not a weakly prime, because it can be changed into another prime (14434321011043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217160505520 + 7217160505521.

It is an arithmetic number, because the mean of its divisors is an integer number (7217160505521).

Almost surely, 2^{14434321011041} is an apocalyptic number.

It is an amenable number.

14434321011041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14434321011041 is an equidigital number, since it uses as much as digits as its factorization.

14434321011041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 14434321011041 its reverse (14011012343441), we get a palindrome (28445333354482).

The spelling of 14434321011041 in words is "fourteen trillion, four hundred thirty-four billion, three hundred twenty-one million, eleven thousand, forty-one".