Base | Representation |
---|---|
bin | 1101001000001111000011… |
… | …0100001101110100101111 |
3 | 1220002222121001102020000202 |
4 | 3102003300310031310233 |
5 | 3343001121331201021 |
6 | 50411223552144115 |
7 | 3016621662230645 |
oct | 322036064156457 |
9 | 56088531366022 |
10 | 14435130334511 |
11 | 46659a4829297 |
12 | 175175bb3803b |
13 | 8092c47baa73 |
14 | 37c942187195 |
15 | 1a0756a1ea0b |
hex | d20f0d0dd2f |
14435130334511 has 2 divisors, whose sum is σ = 14435130334512. Its totient is φ = 14435130334510.
The previous prime is 14435130334439. The next prime is 14435130334553. The reversal of 14435130334511 is 11543303153441.
14435130334511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (11543303153441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14435130334511 - 210 = 14435130333487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14435130334811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7217565167255 + 7217565167256.
It is an arithmetic number, because the mean of its divisors is an integer number (7217565167256).
Almost surely, 214435130334511 is an apocalyptic number.
14435130334511 is a deficient number, since it is larger than the sum of its proper divisors (1).
14435130334511 is an equidigital number, since it uses as much as digits as its factorization.
14435130334511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 14435130334511 its reverse (11543303153441), we get a palindrome (25978433487952).
The spelling of 14435130334511 in words is "fourteen trillion, four hundred thirty-five billion, one hundred thirty million, three hundred thirty-four thousand, five hundred eleven".
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