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14444301442859 is a prime number
BaseRepresentation
bin1101001000110001001101…
…1101001101111100101011
31220010212021012110210120022
43102030103131031330223
53343123412132132414
650415342004551055
73020365153325111
oct322142335157453
956125235423508
1014444301442859
114669880669782
12175349b3b248b
1380a12684a9b2
1437d1721bdab1
151a0ae1c4a18e
hexd231374df2b

14444301442859 has 2 divisors, whose sum is σ = 14444301442860. Its totient is φ = 14444301442858.

The previous prime is 14444301442847. The next prime is 14444301442861. The reversal of 14444301442859 is 95824410344441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14444301442859 is a prime.

Together with 14444301442861, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14444301442859.

It is not a weakly prime, because it can be changed into another prime (14444301442759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222150721429 + 7222150721430.

It is an arithmetic number, because the mean of its divisors is an integer number (7222150721430).

Almost surely, 214444301442859 is an apocalyptic number.

14444301442859 is a deficient number, since it is larger than the sum of its proper divisors (1).

14444301442859 is an equidigital number, since it uses as much as digits as its factorization.

14444301442859 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8847360, while the sum is 53.

The spelling of 14444301442859 in words is "fourteen trillion, four hundred forty-four billion, three hundred one million, four hundred forty-two thousand, eight hundred fifty-nine".