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14444542233551 is a prime number
BaseRepresentation
bin1101001000110010000111…
…0011110000101111001111
31220010212212222120020022002
43102030201303300233033
53343124410302433201
650415421525542515
73020404136112563
oct322144163605717
956125788506262
1014444542233551
114669994582351
121753547b74a3b
1380a1646b76b1
1437d19617d6a3
151a0b07e6076b
hexd2321cf0bcf

14444542233551 has 2 divisors, whose sum is σ = 14444542233552. Its totient is φ = 14444542233550.

The previous prime is 14444542233497. The next prime is 14444542233559. The reversal of 14444542233551 is 15533224544441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14444542233551 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14444542233496 and 14444542233505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14444542233559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7222271116775 + 7222271116776.

It is an arithmetic number, because the mean of its divisors is an integer number (7222271116776).

Almost surely, 214444542233551 is an apocalyptic number.

14444542233551 is a deficient number, since it is larger than the sum of its proper divisors (1).

14444542233551 is an equidigital number, since it uses as much as digits as its factorization.

14444542233551 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608000, while the sum is 47.

Adding to 14444542233551 its reverse (15533224544441), we get a palindrome (29977766777992).

The spelling of 14444542233551 in words is "fourteen trillion, four hundred forty-four billion, five hundred forty-two million, two hundred thirty-three thousand, five hundred fifty-one".