14448111311 has 2 divisors, whose sum is σ = 14448111312. Its totient is φ = 14448111310.

The previous prime is 14448111299. The next prime is 14448111313. The reversal of 14448111311 is 11311184441.

It is a strong prime.

It is an emirp because it is prime and its reverse (11311184441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14448111311 - 2³⁰ = 13374369487 is a prime.

It is a super-2 number, since 2×14448111311² (a number of 21 digits) contains 22 as substring.

Together with 14448111313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14448111313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7224055655 + 7224055656.

It is an arithmetic number, because the mean of its divisors is an integer number (7224055656).

Almost surely, 2^14448111311 is an apocalyptic number.

14448111311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14448111311 is an equidigital number, since it uses as much as digits as its factorization.

14448111311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 29.

Adding to 14448111311 its reverse (11311184441), we get a palindrome (25759295752).

The spelling of 14448111311 in words is "fourteen billion, four hundred forty-eight million, one hundred eleven thousand, three hundred eleven".