Base | Representation |
---|---|
bin | 11010111011011101… |
… | …01001011001100101 |
3 | 1101022120011120202002 |
4 | 31131232221121211 |
5 | 214102044124143 |
6 | 10350332255045 |
7 | 1021160652542 |
oct | 153556513145 |
9 | 41276146662 |
10 | 14457411173 |
11 | 6149916aa7 |
12 | 2975911485 |
13 | 1495301c8a |
14 | 9b2143bc9 |
15 | 5993875b8 |
hex | 35dba9665 |
14457411173 has 2 divisors, whose sum is σ = 14457411174. Its totient is φ = 14457411172.
The previous prime is 14457411121. The next prime is 14457411233. The reversal of 14457411173 is 37111475441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9844013089 + 4613398084 = 99217^2 + 67922^2 .
It is an emirp because it is prime and its reverse (37111475441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14457411173 - 214 = 14457394789 is a prime.
It is a super-3 number, since 3×144574111733 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14457411373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7228705586 + 7228705587.
It is an arithmetic number, because the mean of its divisors is an integer number (7228705587).
Almost surely, 214457411173 is an apocalyptic number.
It is an amenable number.
14457411173 is a deficient number, since it is larger than the sum of its proper divisors (1).
14457411173 is an equidigital number, since it uses as much as digits as its factorization.
14457411173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 47040, while the sum is 38.
The spelling of 14457411173 in words is "fourteen billion, four hundred fifty-seven million, four hundred eleven thousand, one hundred seventy-three".
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