Search a number
-
+
144613353041 is a prime number
BaseRepresentation
bin1000011010101110100…
…0001010011001010001
3111211021100112111101122
42012223220022121101
54332132004244131
6150233502012025
713306440135113
oct2065350123121
9454240474348
10144613353041
115636a516603
122403a877015
13108385a60b1
146ddc2033b3
153b65c50d7b
hex21aba0a651

144613353041 has 2 divisors, whose sum is σ = 144613353042. Its totient is φ = 144613353040.

The previous prime is 144613353029. The next prime is 144613353151. The reversal of 144613353041 is 140353316441.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86051289025 + 58562064016 = 293345^2 + 241996^2 .

It is a cyclic number.

It is not a de Polignac number, because 144613353041 - 222 = 144609158737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144613352992 and 144613353010.

It is not a weakly prime, because it can be changed into another prime (144613353341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72306676520 + 72306676521.

It is an arithmetic number, because the mean of its divisors is an integer number (72306676521).

Almost surely, 2144613353041 is an apocalyptic number.

It is an amenable number.

144613353041 is a deficient number, since it is larger than the sum of its proper divisors (1).

144613353041 is an equidigital number, since it uses as much as digits as its factorization.

144613353041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 144613353041 its reverse (140353316441), we get a palindrome (284966669482).

The spelling of 144613353041 in words is "one hundred forty-four billion, six hundred thirteen million, three hundred fifty-three thousand, forty-one".