Base | Representation |
---|---|
bin | 1000011010101110100… |
… | …0001010011010111111 |
3 | 111211021100112111112201 |
4 | 2012223220022122333 |
5 | 4332132004300101 |
6 | 150233502012331 |
7 | 13306440135331 |
oct | 2065350123277 |
9 | 454240474481 |
10 | 144613353151 |
11 | 5636a5166a3 |
12 | 2403a8770a7 |
13 | 108385a6167 |
14 | 6ddc203451 |
15 | 3b65c50e01 |
hex | 21aba0a6bf |
144613353151 has 2 divisors, whose sum is σ = 144613353152. Its totient is φ = 144613353150.
The previous prime is 144613353041. The next prime is 144613353163. The reversal of 144613353151 is 151353316441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144613353151 - 217 = 144613222079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 144613353151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144613353251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72306676575 + 72306676576.
It is an arithmetic number, because the mean of its divisors is an integer number (72306676576).
Almost surely, 2144613353151 is an apocalyptic number.
144613353151 is a deficient number, since it is larger than the sum of its proper divisors (1).
144613353151 is an equidigital number, since it uses as much as digits as its factorization.
144613353151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 37.
Adding to 144613353151 its reverse (151353316441), we get a palindrome (295966669592).
The spelling of 144613353151 in words is "one hundred forty-four billion, six hundred thirteen million, three hundred fifty-three thousand, one hundred fifty-one".
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