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14468113301 is a prime number
BaseRepresentation
bin11010111100101110…
…11110001110010101
31101100022022022022012
431132113132032111
5214112314111201
610351353514005
71021350635225
oct153627361625
941308268265
1014468113301
116154966734
122979412905
1314975ab2b5
149b372c085
1559a29d5bb
hex35e5de395

14468113301 has 2 divisors, whose sum is σ = 14468113302. Its totient is φ = 14468113300.

The previous prime is 14468113291. The next prime is 14468113327. The reversal of 14468113301 is 10331186441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7370050801 + 7098062500 = 85849^2 + 84250^2 .

It is an emirp because it is prime and its reverse (10331186441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14468113301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14468113001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7234056650 + 7234056651.

It is an arithmetic number, because the mean of its divisors is an integer number (7234056651).

Almost surely, 214468113301 is an apocalyptic number.

It is an amenable number.

14468113301 is a deficient number, since it is larger than the sum of its proper divisors (1).

14468113301 is an equidigital number, since it uses as much as digits as its factorization.

14468113301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 14468113301 its reverse (10331186441), we get a palindrome (24799299742).

The spelling of 14468113301 in words is "fourteen billion, four hundred sixty-eight million, one hundred thirteen thousand, three hundred one".