Base | Representation |
---|---|
bin | 10001010000111… |
… | …11001101000101 |
3 | 101002112012012021 |
4 | 20220133031011 |
5 | 244034100201 |
6 | 22212123141 |
7 | 3406021456 |
oct | 1050371505 |
9 | 332465167 |
10 | 144831301 |
11 | 7483199a |
12 | 406064b1 |
13 | 2400c3c4 |
14 | 1534112d |
15 | caacea1 |
hex | 8a1f345 |
144831301 has 2 divisors, whose sum is σ = 144831302. Its totient is φ = 144831300.
The previous prime is 144831293. The next prime is 144831377. The reversal of 144831301 is 103138441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98604900 + 46226401 = 9930^2 + 6799^2 .
It is a cyclic number.
It is not a de Polignac number, because 144831301 - 23 = 144831293 is a prime.
It is a super-2 number, since 2×1448313012 = 41952211498705202, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144838301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72415650 + 72415651.
It is an arithmetic number, because the mean of its divisors is an integer number (72415651).
Almost surely, 2144831301 is an apocalyptic number.
It is an amenable number.
144831301 is a deficient number, since it is larger than the sum of its proper divisors (1).
144831301 is an equidigital number, since it uses as much as digits as its factorization.
144831301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
The square root of 144831301 is about 12034.5876954717. The cubic root of 144831301 is about 525.1549668004.
Adding to 144831301 its reverse (103138441), we get a palindrome (247969742).
The spelling of 144831301 in words is "one hundred forty-four million, eight hundred thirty-one thousand, three hundred one".
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