Search a number
-
+
1449430511 is a prime number
BaseRepresentation
bin101011001100100…
…1000110111101111
310202000100200212112
41112121020313233
510432023234021
6355454154235
750626645634
oct12631106757
93660320775
101449430511
11684190661
123454b297b
131a13978b9
14da6dc18b
15873aad5b
hex56648def

1449430511 has 2 divisors, whose sum is σ = 1449430512. Its totient is φ = 1449430510.

The previous prime is 1449430481. The next prime is 1449430517. The reversal of 1449430511 is 1150349441.

It is a strong prime.

It is an emirp because it is prime and its reverse (1150349441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1449430511 is a prime.

It is a super-2 number, since 2×14494305112 = 4201697612435442242, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1449430517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 724715255 + 724715256.

It is an arithmetic number, because the mean of its divisors is an integer number (724715256).

Almost surely, 21449430511 is an apocalyptic number.

1449430511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1449430511 is an equidigital number, since it uses as much as digits as its factorization.

1449430511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

The square root of 1449430511 is about 38071.3870380368. The cubic root of 1449430511 is about 1131.7029979836.

Adding to 1449430511 its reverse (1150349441), we get a palindrome (2599779952).

The spelling of 1449430511 in words is "one billion, four hundred forty-nine million, four hundred thirty thousand, five hundred eleven".