Base | Representation |
---|---|
bin | 1101001100000101100100… |
… | …0010111000101101101011 |
3 | 1220100022101202221100102112 |
4 | 3103001121002320231223 |
5 | 3400042132200120412 |
6 | 50501450141152535 |
7 | 3024453551101205 |
oct | 323013102705553 |
9 | 56308352840375 |
10 | 14501303520107 |
11 | 4690a71875028 |
12 | 176254925b74b |
13 | 81260c16cca1 |
14 | 381c1c84b775 |
15 | 1a232b1b9722 |
hex | d30590b8b6b |
14501303520107 has 2 divisors, whose sum is σ = 14501303520108. Its totient is φ = 14501303520106.
The previous prime is 14501303520059. The next prime is 14501303520139. The reversal of 14501303520107 is 70102530310541.
It is an a-pointer prime, because the next prime (14501303520139) can be obtained adding 14501303520107 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14501303520107 is a prime.
It is not a weakly prime, because it can be changed into another prime (14501303520307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7250651760053 + 7250651760054.
It is an arithmetic number, because the mean of its divisors is an integer number (7250651760054).
Almost surely, 214501303520107 is an apocalyptic number.
14501303520107 is a deficient number, since it is larger than the sum of its proper divisors (1).
14501303520107 is an equidigital number, since it uses as much as digits as its factorization.
14501303520107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12600, while the sum is 32.
Adding to 14501303520107 its reverse (70102530310541), we get a palindrome (84603833830648).
The spelling of 14501303520107 in words is "fourteen trillion, five hundred one billion, three hundred three million, five hundred twenty thousand, one hundred seven".
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