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145013035201319 is a prime number
BaseRepresentation
bin100000111110001101111010…
…011100110111001100100111
3201000110002222202101111121102
4200332031322130313030213
5123001343144002420234
61232230022501110315
742354563124316505
oct4076157234671447
9630402882344542
10145013035201319
114222975698645a
12143205b80b839b
1362bb89424cc2c
1427b494dd63675
1511b71c62b4c7e
hex83e37a737327

145013035201319 has 2 divisors, whose sum is σ = 145013035201320. Its totient is φ = 145013035201318.

The previous prime is 145013035201297. The next prime is 145013035201373. The reversal of 145013035201319 is 913102530310541.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145013035201319 is a prime.

It is a super-2 number, since 2×1450130352013192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145013035201219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72506517600659 + 72506517600660.

It is an arithmetic number, because the mean of its divisors is an integer number (72506517600660).

Almost surely, 2145013035201319 is an apocalyptic number.

145013035201319 is a deficient number, since it is larger than the sum of its proper divisors (1).

145013035201319 is an equidigital number, since it uses as much as digits as its factorization.

145013035201319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48600, while the sum is 38.

The spelling of 145013035201319 in words is "one hundred forty-five trillion, thirteen billion, thirty-five million, two hundred one thousand, three hundred nineteen".