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145013342101 is a prime number
BaseRepresentation
bin1000011100001101110…
…1111111111110010101
3111212022020012001020021
42013003131333332111
54333441403421401
6150341311105141
713322365033015
oct2070335777625
9455266161207
10145013342101
1156555284281
12241308121b1
13108a0412704
1470393a3c45
153b8ae112a1
hex21c377ff95

145013342101 has 2 divisors, whose sum is σ = 145013342102. Its totient is φ = 145013342100.

The previous prime is 145013342093. The next prime is 145013342161. The reversal of 145013342101 is 101243310541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143690274225 + 1323067876 = 379065^2 + 36374^2 .

It is a cyclic number.

It is not a de Polignac number, because 145013342101 - 23 = 145013342093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145013342161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72506671050 + 72506671051.

It is an arithmetic number, because the mean of its divisors is an integer number (72506671051).

Almost surely, 2145013342101 is an apocalyptic number.

It is an amenable number.

145013342101 is a deficient number, since it is larger than the sum of its proper divisors (1).

145013342101 is an equidigital number, since it uses as much as digits as its factorization.

145013342101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 145013342101 its reverse (101243310541), we get a palindrome (246256652642).

The spelling of 145013342101 in words is "one hundred forty-five billion, thirteen million, three hundred forty-two thousand, one hundred one".