145040113411 has 2 divisors, whose sum is σ = 145040113412. Its totient is φ = 145040113410.

The previous prime is 145040113357. The next prime is 145040113417. The reversal of 145040113411 is 114311040541.

It is a strong prime.

It is an emirp because it is prime and its reverse (114311040541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145040113411 - 2¹³ = 145040105219 is a prime.

It is not a weakly prime, because it can be changed into another prime (145040113417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72520056705 + 72520056706.

It is an arithmetic number, because the mean of its divisors is an integer number (72520056706).

Almost surely, 2^145040113411 is an apocalyptic number.

145040113411 is a deficient number, since it is larger than the sum of its proper divisors (1).

145040113411 is an equidigital number, since it uses as much as digits as its factorization.

145040113411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 145040113411 its reverse (114311040541), we get a palindrome (259351153952).

The spelling of 145040113411 in words is "one hundred forty-five billion, forty million, one hundred thirteen thousand, four hundred eleven".