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145040113357 is a prime number
BaseRepresentation
bin1000011100010100010…
…0000111111011001101
3111212101002120011111021
42013011010013323031
54334020232111412
6150344104554141
713323141423226
oct2070504077315
9455332504437
10145040113357
11565693a9987
1224139782951
13108a5b26ba9
14703cb7224d
153b8d44d607
hex21c5107ecd

145040113357 has 2 divisors, whose sum is σ = 145040113358. Its totient is φ = 145040113356.

The previous prime is 145040113343. The next prime is 145040113411. The reversal of 145040113357 is 753311040541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144653951556 + 386161801 = 380334^2 + 19651^2 .

It is a cyclic number.

It is not a de Polignac number, because 145040113357 - 211 = 145040111309 is a prime.

It is a super-2 number, since 2×1450401133572 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145040113457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72520056678 + 72520056679.

It is an arithmetic number, because the mean of its divisors is an integer number (72520056679).

Almost surely, 2145040113357 is an apocalyptic number.

It is an amenable number.

145040113357 is a deficient number, since it is larger than the sum of its proper divisors (1).

145040113357 is an equidigital number, since it uses as much as digits as its factorization.

145040113357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 145040113357 its reverse (753311040541), we get a palindrome (898351153898).

The spelling of 145040113357 in words is "one hundred forty-five billion, forty million, one hundred thirteen thousand, three hundred fifty-seven".