Base | Representation |
---|---|
bin | 1000011100010100010… |
… | …0000111111011001101 |
3 | 111212101002120011111021 |
4 | 2013011010013323031 |
5 | 4334020232111412 |
6 | 150344104554141 |
7 | 13323141423226 |
oct | 2070504077315 |
9 | 455332504437 |
10 | 145040113357 |
11 | 565693a9987 |
12 | 24139782951 |
13 | 108a5b26ba9 |
14 | 703cb7224d |
15 | 3b8d44d607 |
hex | 21c5107ecd |
145040113357 has 2 divisors, whose sum is σ = 145040113358. Its totient is φ = 145040113356.
The previous prime is 145040113343. The next prime is 145040113411. The reversal of 145040113357 is 753311040541.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 144653951556 + 386161801 = 380334^2 + 19651^2 .
It is a cyclic number.
It is not a de Polignac number, because 145040113357 - 211 = 145040111309 is a prime.
It is a super-2 number, since 2×1450401133572 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145040113457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72520056678 + 72520056679.
It is an arithmetic number, because the mean of its divisors is an integer number (72520056679).
Almost surely, 2145040113357 is an apocalyptic number.
It is an amenable number.
145040113357 is a deficient number, since it is larger than the sum of its proper divisors (1).
145040113357 is an equidigital number, since it uses as much as digits as its factorization.
145040113357 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 145040113357 its reverse (753311040541), we get a palindrome (898351153898).
The spelling of 145040113357 in words is "one hundred forty-five billion, forty million, one hundred thirteen thousand, three hundred fifty-seven".
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