Base | Representation |
---|---|
bin | 11011000001010011… |
… | …01110000110110111 |
3 | 1101102222110002021011 |
4 | 31200221232012313 |
5 | 214202122421013 |
6 | 10355243333051 |
7 | 1022324542114 |
oct | 154051560667 |
9 | 41388402234 |
10 | 14506451383 |
11 | 61745716a6 |
12 | 298a221187 |
13 | 14a2512558 |
14 | 9b886b90b |
15 | 59d822c3d |
hex | 360a6e1b7 |
14506451383 has 2 divisors, whose sum is σ = 14506451384. Its totient is φ = 14506451382.
The previous prime is 14506451359. The next prime is 14506451423. The reversal of 14506451383 is 38315460541.
It is an a-pointer prime, because the next prime (14506451423) can be obtained adding 14506451383 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14506451383 is a prime.
It is a super-2 number, since 2×145064513832 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14506451353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7253225691 + 7253225692.
It is an arithmetic number, because the mean of its divisors is an integer number (7253225692).
Almost surely, 214506451383 is an apocalyptic number.
14506451383 is a deficient number, since it is larger than the sum of its proper divisors (1).
14506451383 is an equidigital number, since it uses as much as digits as its factorization.
14506451383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 14506451383 in words is "fourteen billion, five hundred six million, four hundred fifty-one thousand, three hundred eighty-three".
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