Base | Representation |
---|---|
bin | 1101001100100110001000… |
… | …0101001111110110000111 |
3 | 1220101010221222201000201202 |
4 | 3103021202011033312013 |
5 | 3400213033014144204 |
6 | 50505453411013115 |
7 | 3025213305040436 |
oct | 323114205176607 |
9 | 56333858630652 |
10 | 14510045068679 |
11 | 469474818a936 |
12 | 176418889a19b |
13 | 8133a320bb34 |
14 | 38240b7c711d |
15 | 1a268d842e1e |
hex | d326214fd87 |
14510045068679 has 2 divisors, whose sum is σ = 14510045068680. Its totient is φ = 14510045068678.
The previous prime is 14510045068657. The next prime is 14510045068681. The reversal of 14510045068679 is 97686054001541.
14510045068679 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14510045068679 - 212 = 14510045064583 is a prime.
Together with 14510045068681, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14510045061679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7255022534339 + 7255022534340.
It is an arithmetic number, because the mean of its divisors is an integer number (7255022534340).
Almost surely, 214510045068679 is an apocalyptic number.
14510045068679 is a deficient number, since it is larger than the sum of its proper divisors (1).
14510045068679 is an equidigital number, since it uses as much as digits as its factorization.
14510045068679 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 56.
The spelling of 14510045068679 in words is "fourteen trillion, five hundred ten billion, forty-five million, sixty-eight thousand, six hundred seventy-nine".
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