Search a number
-
+
14515004113 is a prime number
BaseRepresentation
bin11011000010010100…
…10110001011010001
31101110120112121101221
431201022112023101
5214211320112423
610400150525041
71022460333151
oct154112261321
941416477357
1014515004113
116179383475
122991066781
1314a421843c
149b9a56761
1559e461e5d
hex3612962d1

14515004113 has 2 divisors, whose sum is σ = 14515004114. Its totient is φ = 14515004112.

The previous prime is 14515004111. The next prime is 14515004143. The reversal of 14515004113 is 31140051541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12379455169 + 2135548944 = 111263^2 + 46212^2 .

It is an emirp because it is prime and its reverse (31140051541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14515004113 - 21 = 14515004111 is a prime.

Together with 14515004111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14515004111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7257502056 + 7257502057.

It is an arithmetic number, because the mean of its divisors is an integer number (7257502057).

Almost surely, 214515004113 is an apocalyptic number.

It is an amenable number.

14515004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14515004113 is an equidigital number, since it uses as much as digits as its factorization.

14515004113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 14515004113 its reverse (31140051541), we get a palindrome (45655055654).

The spelling of 14515004113 in words is "fourteen billion, five hundred fifteen million, four thousand, one hundred thirteen".