Base | Representation |
---|---|
bin | 100001000000100011010110… |
… | …111011011010010000111100 |
3 | 201001000110011212011102122122 |
4 | 201000203112323122100330 |
5 | 123012010312112044400 |
6 | 1232431441353302112 |
7 | 42402303451012616 |
oct | 4100432673322074 |
9 | 631013155142578 |
10 | 145173500503100 |
11 | 42290810406743 |
12 | 1434771b704938 |
13 | 6300a57a13344 |
14 | 27bc613599db6 |
15 | 11bb468a14685 |
hex | 8408d6eda43c |
145173500503100 has 36 divisors (see below), whose sum is σ = 315071328482904. Its totient is φ = 58061136166080.
The previous prime is 145173500503079. The next prime is 145173500503117. The reversal of 145173500503100 is 1305005371541.
It is a super-3 number, since 3×1451735005031003 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 102594227 + ... + 103999626.
Almost surely, 2145173500503100 is an apocalyptic number.
145173500503100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
145173500503100 is an abundant number, since it is smaller than the sum of its proper divisors (169897827979804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
145173500503100 is a wasteful number, since it uses less digits than its factorization.
145173500503100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 206600894 (or 206600887 counting only the distinct ones).
The product of its (nonzero) digits is 31500, while the sum is 35.
Adding to 145173500503100 its reverse (1305005371541), we get a palindrome (146478505874641).
The spelling of 145173500503100 in words is "one hundred forty-five trillion, one hundred seventy-three billion, five hundred million, five hundred three thousand, one hundred".
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