Base | Representation |
---|---|
bin | 1000011100111011000… |
… | …1111101000011110111 |
3 | 111212210110021212220002 |
4 | 2013032301331003313 |
5 | 4334333444404143 |
6 | 150412210501515 |
7 | 13330161114302 |
oct | 2071661750367 |
9 | 455713255802 |
10 | 145203122423 |
11 | 56642417017 |
12 | 2418429489b |
13 | 1090082c168 |
14 | 7056685b39 |
15 | 3b9c8ec5b8 |
hex | 21cec7d0f7 |
145203122423 has 2 divisors, whose sum is σ = 145203122424. Its totient is φ = 145203122422.
The previous prime is 145203122399. The next prime is 145203122447. The reversal of 145203122423 is 324221302541.
It is a balanced prime because it is at equal distance from previous prime (145203122399) and next prime (145203122447).
It is an emirp because it is prime and its reverse (324221302541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145203122423 - 28 = 145203122167 is a prime.
It is a super-2 number, since 2×1452031224232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145203122453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72601561211 + 72601561212.
It is an arithmetic number, because the mean of its divisors is an integer number (72601561212).
Almost surely, 2145203122423 is an apocalyptic number.
145203122423 is a deficient number, since it is larger than the sum of its proper divisors (1).
145203122423 is an equidigital number, since it uses as much as digits as its factorization.
145203122423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 145203122423 its reverse (324221302541), we get a palindrome (469424424964).
The spelling of 145203122423 in words is "one hundred forty-five billion, two hundred three million, one hundred twenty-two thousand, four hundred twenty-three".
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